definite-integral

Question: The value of $\int_{0}^{1}{{{x}^{2}}{{e}^{x}}dx}$is equal to



1) $e-2$
2) $e+2$
3) ${{e}^{2}}-2$
4) ${{e}^{2}}$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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