definite-integral

Question: If ${{I}_{n}}=\int_{0}^{\pi /4}{{{\tan }^{n}}\theta \,d\theta ,}$ then ${{I}_{8}}+{{I}_{6}}$ equals



1) $\frac{1}{4}$
2) $\frac{1}{5}$
3) $\frac{1}{6}$
4) $\frac{1}{7}$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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