definite-integral

Question: If for non-zero $x,$ $af(x)+bf\left( \frac{1}{x} \right)=\frac{1}{x}-5,$ where $a\ne b,$ then $\int_{1}^{2}{f(x)\,dx=}$



1) $\frac{1}{({{a}^{2}}+{{b}^{2}})}\left[ a\log 2-5a+\frac{7}{2}b \right]$
2) $\frac{1}{({{a}^{2}}-{{b}^{2}})}\left[ a\log 2-5a+\frac{7}{2}b \right]$
3) $\frac{1}{({{a}^{2}}-{{b}^{2}})}\left[ a\log 2-5a-\frac{7}{2}b \right]$
4) $\frac{1}{({{a}^{2}}+{{b}^{2}})}\left[ a\log 2-5a-\frac{7}{2}b \right]$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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