definite-integral

Question: If $\int_{0}^{1}{x\log \left( 1+\frac{x}{2} \right)}\,dx=a+b\log \frac{2}{3},$ then



1) $a=\frac{3}{2},\,\,\,b=\frac{3}{2}$
2) $a=\frac{3}{4},\,\,\,b=-\frac{3}{4}$
3) $a=\frac{3}{4},\,\,\,b=\frac{3}{2}$
4) $a=b$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

Rate this question:

Average rating: (0 votes)

Previous Question Next Question