definite-integral

Question: $\int_{0}^{1}{\frac{{{e}^{-x}}}{1+{{e}^{-x}}}}\,dx=$



1) $\log \left( \frac{1+e}{e} \right)-\frac{1}{e}+1$
2) $\log \left( \frac{1+e}{2e} \right)-\frac{1}{e}+1$
3) $\log \left( \frac{1+e}{2e} \right)+\frac{1}{e}-1$
4) None of these
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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