indefinite-integration

Question: $\int{\frac{{{e}^{\sqrt{x}}}}{\sqrt{x}}dx}=$

1) ${{e}^{\sqrt{x}}}$

2) $\frac{{{e}^{\sqrt{x}}}}{2}$

3) $2\,{{e}^{\sqrt{x}}}$

4) $\sqrt{x}\,.\,{{e}^{\sqrt{x}}}$

Solution:

Explanation: No Explanation

Integration by substitution

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