indefinite-integration

Question: $\int_{{}}^{{}}{{{\sin }^{2}}x\cos x\ dx}$ is equal to

1) $\frac{{{\cos }^{2}}x}{2}+c$

2) $\frac{{{\sin }^{2}}x}{3}+c$

3) $\frac{{{\sin }^{3}}x}{3}+c$

4) $-\frac{{{\cos }^{2}}x}{2}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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