indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{x}\log x\ dx}$ is equal to



1) $\frac{1}{2}\log x+c$
2) $\frac{1}{2}{{(\log x)}^{2}}+c$
3) $\frac{1}{2}\log {{(x)}^{2}}+c$
4) $\log x+c$
Solution: Explanation: No Explanation
Integration by substitution

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