$\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}$ is equal to

Question

Accepted Answer

$\frac{4}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c$

Answer

$\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c$

Answer

$\frac{1}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c$

Answer

$\frac{1}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c$

indefinite-integration