indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{4{{\cos }^{3}}2x-3\cos 2x}}=$

1) $\frac{1}{3}\log [\sec 6x+\tan 6x]+c$

2) $\frac{1}{6}\log [\sec 6x+\tan 6x]+c$

3) $\log [\sec 6x+\tan 6x]+c$

4) None of these

Solution:

Explanation: No Explanation

Fundamental integration

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