indefinite-integration

Question: $\int_{{}}^{{}}{{{\sec }^{p}}x\tan x\ dx=}$

1) $\frac{{{\sec }^{p+1}}x}{p+1}+c$

2) $\frac{{{\sec }^{p}}x}{p}+c$

3) $\frac{{{\tan }^{p+1}}x}{p+1}+c$

4) $\frac{{{\tan }^{p}}x}{p}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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