indefinite-integration

Question: $\int_{{}}^{{}}{\sqrt{1+{{x}^{2}}}\ dx=}$



1) $\frac{x}{2}\sqrt{1+{{x}^{2}}}+\frac{1}{2}\log (x+\sqrt{1+{{x}^{2}}})+c$
2) $\frac{2}{3}{{(1+{{x}^{2}})}^{3/2}}+c$
3) $\frac{2}{3}x{{(1+{{x}^{2}})}^{3/2}}+c$
4) None of these
Solution: Explanation: No Explanation
Fundamental integration

Rate this question:

Average rating: (0 votes)

Previous Question Next Question