indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{4{{x}^{2}}+9}=}$

1) $\frac{1}{2}{{\tan }^{-1}}\left( \frac{2x}{3} \right)+c$

2) $\frac{3}{2}{{\tan }^{-1}}\left( \frac{2x}{3} \right)+c$

3) $\frac{1}{6}{{\tan }^{-1}}\left( \frac{2x}{3} \right)+c$

4) $\frac{1}{6}{{\tan }^{-1}}\left( \frac{3x}{2} \right)+c$

Solution:

Explanation: No Explanation

Fundamental integration

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