indefinite-integration

Question: $\int_{{}}^{{}}{{{\sec }^{2/3}}x\,\text{cose}{{\text{c}}^{4/3}}x\ dx=}$

1) $-3{{(\tan x)}^{1/3}}+c$

2) $-3{{(\tan x)}^{-1/3}}+c$

3) $3{{(\tan x)}^{-1/3}}+c$

4) ${{(\tan x)}^{-1/3}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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