indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{{{x}^{2}}}{{(2x+1)}^{3}}}dx=$



1) $4{{x}^{2}}+12x+6\log x-\frac{1}{x}+c$
2) $4{{x}^{2}}+12x-6\log x-\frac{2}{x}+c$
3) $2{{x}^{2}}+8x+3\log x-\frac{2}{x}+c$
4) $8{{x}^{2}}+6x+6\log x+\frac{2}{x}+c$
Solution: Explanation: No Explanation
Fundamental integration

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