differentiation

Question: A particle is moving on a straight line, where its position s (in metre) is a function of time t (in seconds) given by $s=a{{t}^{2}}+bt+6,t\ge 0$ . If it is known that the particle comes to rest after 4 seconds at a distance of 16 metre from the starting position $(t=0)$ , then the retardation in its motion is



1) $-1m/{{\sec }^{2}}$
2) $\frac{5}{4}m/{{\sec }^{2}}$
3) $-\frac{1}{2}m/{{\sec }^{2}}$
4) $-\frac{5}{4}m/{{\sec }^{2}}$
Solution: Explanation: No Explanation
Application of Derivatives

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