Categories > differentiation > Implicit-function > If ${x^2} + {y^2} = t - \frac{1}{t},$${x^4} + {y^4} = {t^2} + \frac{1}{{{t^2}}}$, then ${x^3}y\frac{{dy}}{{dx}} = $

differentiation

Question: If ${x^2} + {y^2} = t - \frac{1}{t},$${x^4} + {y^4} = {t^2} + \frac{1}{{{t^2}}}$, then ${x^3}y\frac{{dy}}{{dx}} = $


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Solution: Explanation: Explanation
Implicit-function

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