differentiation

Question: If $\tan (x + y) + \tan (x - y) = 1,$then $\frac{{dy}}{{dx}} = $

1) $\frac{{{{\sec }^2}(x + y) + {{\sec }^2}(x - y)}}{{{{\sec }^2}(x + y) - {{\sec }^2}(x - y)}}$

2) $\frac{{{{\sec }^2}(x + y) + {{\sec }^2}(x - y)}}{{{{\sec }^2}(x - y) - {{\sec }^2}(x + y)}}$

3) $\frac{{{{\sec }^2}(x + y) - {{\sec }^2}(x - y)}}{{{{\sec }^2}(x + y) + {{\sec }^2}(x - y)}}$

4) None of these

Solution:

Explanation: Explanation

Implicit-function

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