$\frac{d}{{dx}}\left\{ {{e^x}\log (1 + {x^2})} \right\} = $

Question

Accepted Answer

${e^x}\left[ {\log (1 + {x^2}) + \frac{{2x}}{{1 + {x^2}}}} \right]$

Answer

${e^x}\left[ {\log (1 + {x^2}) - \frac{{2x}}{{1 + {x^2}}}} \right]$

Answer

${e^x}\left[ {\log (1 + {x^2}) + \frac{x}{{1 + {x^2}}}} \right]$

Answer

${e^x}\left[ {\log (1 + {x^2}) - \frac{x}{{1 + {x^2}}}} \right]$

differentiation