differentiation

Question: If $y = \frac{{{e^{2x}} + {e^{ - 2x}}}}{{{e^{2x}} - {e^{ - 2x}}}}$, then $\frac{{dy}}{{dx}} = $

1) $\frac{{ - 8}}{{{{({e^{2x}} - {e^{ - 2x}})}^2}}}$

2) $\frac{8}{{{{({e^{2x}} - {e^{ - 2x}})}^2}}}$

3) $\frac{{ - 4}}{{{{({e^{2x}} - {e^{ - 2x}})}^2}}}$

4) $\frac{4}{{{{({e^{2x}} - {e^{ - 2x}})}^2}}}$

Solution:

Explanation: Explanation

standard-differentiation

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)