differentiation

Question: If $y = \frac{{2{{(x - \sin x)}^{3/2}}}}{{\sqrt x }}$, then $\frac{{dy}}{{dx}} = $



1) $\frac{{2{{(x - \sin x)}^{3/2}}}}{{\sqrt x }}\left[ {\frac{3}{2}.\frac{{1 - \cos x}}{{1 - \sin x}} - \frac{1}{{2x}}} \right]$
2) $\frac{{2{{(x - \sin x)}^{3/2}}}}{{\sqrt x }}\left[ {\frac{3}{2}.\frac{{1 - \cos x}}{{x - \sin x}} - \frac{1}{{2x}}} \right]$
3) $\frac{{2{{(x - \sin x)}^{1/2}}}}{{\sqrt x }}\left[ {\frac{3}{2}.\frac{{1 - \cos x}}{{x - \sin x}} - \frac{1}{{2x}}} \right]$
4) None of these
Solution: Explanation: Explanation
standard-differentiation

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