differentiation

Question: If $y={{e}^{{{\tan }^{-1}}x}}$, then $(1+{{x}^{2}})\frac{{{d}^{2}}y}{d{{x}^{2}}}=$



1) $(1-2x)\frac{dy}{dx}$
2) $-2x\frac{dy}{dx}$
3) $-x\frac{dy}{dx}$
4) 0
Solution: Explanation: No Explanation
Differentiation by substitution Higher order derivatives

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