differentiation

Related Questions

• $\frac{d}{dx}\left( {{\tan }^{-1}}\frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)$ is equal to

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• $\frac{{{d}^{2}}}{d{{x}^{2}}}(2\cos x\,\cos 3x)=$

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• If ${{u}^{2}}={{(x-a)}^{2}}+{{(y-b)}^{2}}+{{(z-c)}^{2}}$, then $\sum \frac{{{\partial }^{2}}u}{\partial {{x}^{2}}}=$

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• If $y = {\tan ^{ - 1}}\frac{{4x}}{{1 + 5{x^2}}} + {\tan ^{ - 1}}\frac{{2 + 3x}}{{3 - 2x}}$, then $\frac{{dy}}{{dx}} = $

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• If $y = \frac{{{a^{{{\cos }^{ - 1}}x}}}}{{1 + {a^{{{\cos }^{ - 1}}x}}}}$and $z = {a^{{{\cos }^{ - 1}}x}}$, then $\frac{{dy}}{{dx}}$=

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