fun-lim

Question: $\underset{x\to 0}{\mathop{\lim }}\,\frac{\log (a+x)-\log a}{x}+k\underset{x\to e}{\mathop{\lim }}\,\frac{\log x-1}{x-e}=1,$ then



1) $k=e\left( 1-\frac{1}{a} \right)$
2) $k=e(1+a)$
3) $k=e(2-a)$
4) The equality is not possible
Solution: Explanation: No Explanation
Limits

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