fun-lim

Question: Let $g(x)=1+x-[x]$ and $f(x) = \begin{cases} - 1,\;x {\rm{0}} \end{cases}$ then for all $x,\ f(g(x))$ is equal to



1) x
2) 1
3) $f(x)$
4) $g(x)$
Solution: Explanation: No Explanation
Functions

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