fun-lim

Question: $\underset{\alpha \to \beta }{\mathop{\lim }}\,\left[ \frac{{{\sin }^{2}}\alpha -{{\sin }^{2}}\beta }{{{\alpha }^{2}}-{{\beta }^{2}}} \right]=$



1) 0
2) 1
3) $\frac{\sin \beta }{\beta }$
4) $\frac{\sin 2\beta }{2\beta }$
Solution: Explanation: No Explanation
Limits

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