vectors-m

Question: The area of the parallelogram whose diagonals are $\frac{3}{2}\mathbf{i}+\frac{1}{2}\mathbf{j}-\mathbf{k}$ and $2\mathbf{i}-6\mathbf{j}+8\mathbf{k}$ is

1) ${{a}^{2}}+{{b}^{2}}+{{c}^{2}}=bc+ca+ab$

2) $5\sqrt{2}$

3) $({{a}^{2}}+ab,\,{{b}^{2}}+ab,\,-ab)$

4) $(-bc,\,{{b}^{2}}+bc,\,{{c}^{2}}+bc),$

Solution:

Explanation: No Explanation

Vector Product Cross Product of two vectors

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