vectors-m

Question: If $\mathbf{a}=\mathbf{i}+\mathbf{j}+\mathbf{k},\,\mathbf{b}=\mathbf{i}+3\mathbf{j}+5\mathbf{k}$ and $\mathbf{c}=7\mathbf{i}+9\mathbf{j}+11\mathbf{k}$, then the area of the parallelogram having diagonals a + b and b + c is



1) $4\sqrt{6}$
2) $\frac{1}{2}\sqrt{21}$
3) $\frac{\sqrt{6}}{2}$
4) $\sqrt{6}$
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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