vectors-m

Question: A unit vector perpendicular to the plane determined by the points $P\,(1,\,\,-1,\,\,2),\,\,Q\,(2,\,\,0,\,-1)$ and $R\,(0,\,\,2,\,\,1)$ is



1) $\frac{2\mathbf{i}-\mathbf{j}+\mathbf{k}}{\sqrt{6}}$
2) $\frac{2\mathbf{i}+\mathbf{j}+\mathbf{k}}{\sqrt{6}}$
3) $\frac{-2\mathbf{i}+\mathbf{j}+\mathbf{k}}{\sqrt{6}}$
4) $\frac{2\mathbf{i}+\mathbf{j}-\mathbf{k}}{\sqrt{6}}$
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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