inv-trig

Question: If $\angle A={{90}^{o}}$ in the triangle ABC, then ${{\tan }^{-1}}\left( \frac{c}{a+b} \right)+{{\tan }^{-1}}\left( \frac{b}{a+c} \right)=$



1) 0
2) 1
3) $\pi /4$
4) $\pi /6$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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