inv-trig

Question: ${{\tan }^{-1}}\left[ \frac{\cos x}{1+\sin x} \right]=$



1) $\frac{\pi }{4}-\frac{x}{2}$
2) $\frac{\pi }{4}+\frac{x}{2}$
3) $\frac{x}{2}$
4) $\frac{\pi }{4}-x$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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