inv-trig

Question: ${{\cot }^{-1}}[{{(\cos \alpha )}^{1/2}}]-{{\tan }^{-1}}[{{(\cos \alpha )}^{1/2}}]=x,$then $\sin x=$



1) ${{\tan }^{2}}\left( \frac{\alpha }{2} \right)$
2) ${{\cot }^{2}}\left( \frac{\alpha }{2} \right)$
3) $\tan \alpha $
4) $\cot \left( \frac{\alpha }{2} \right)$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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