inv-trig

Question: ${{\tan }^{-1}}\frac{{{c}_{1}}x-y}{{{c}_{1}}y+x}+{{\tan }^{-1}}\frac{{{c}_{2}}-{{c}_{1}}}{1+{{c}_{2}}{{c}_{1}}}+$ ${{\tan }^{-1}}\frac{{{c}_{3}}-{{c}_{2}}}{1+{{c}_{3}}{{c}_{2}}}+...+{{\tan }^{-1}}\frac{1}{{{c}_{n}}}=$

1) ${{\tan }^{-1}}\frac{y}{x}$

2) ${{\tan }^{-1}}yx$

3) ${{\tan }^{-1}}\frac{x}{y}$

4) ${{\tan }^{-1}}(x-y)$

Solution:

Explanation: No Explanation

Inverse trigonometric functions

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