inv-trig

Question: If ${{\tan }^{-1}}\frac{x-1}{x+1}+{{\tan }^{-1}}\frac{2x-1}{2x+1}={{\tan }^{-1}}\frac{23}{36},$then $x =$



1) $\frac{3}{4},\frac{-3}{8}$
2) $\frac{3}{4},\frac{3}{8}$
3) $\frac{4}{3},\frac{3}{8}$
4) None of these
Solution: Explanation: No Explanation
Inverse trigonometric functions

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