inv-trig

Related Questions

• A solution of the equation ${{\tan }^{-1}}(1+x)$ $+{{\tan }^{-1}}(1-x)$ $=\frac{\pi }{2}$ is

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• The value of ${{\cos }^{-1}}\left( \cos \frac{5\pi }{3} \right)+{{\sin }^{-1}}\left( \sin \frac{5\pi }{3} \right)$is

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• $\sin \left\{ {{\tan }^{-1}}\left( \frac{1-{{x}^{2}}}{2x} \right)+{{\cos }^{-1}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right) \right\}$is equal to

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• If $x$takes non-positive permissible value, then ${{\sin }^{-1}}x$=

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• If $\angle A={{90}^{o}}$ in the triangle ABC, then ${{\tan }^{-1}}\left( \frac{c}{a+b} \right)+{{\tan }^{-1}}\left( \frac{b}{a+c} \right)=$

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