inv-trig

Question: ${{\tan }^{-1}}\frac{1}{\sqrt{{{x}^{2}}-1}}=$

1) $\frac{\pi }{2}+\text{cose}{{\text{c}}^{-1}}x$

2) $\frac{\pi }{2}+{{\sec }^{-1}}x$

3) $\text{cose}{{\text{c}}^{-1}}x$

4) ${{\sec }^{-1}}x$

Solution:

Explanation: No Explanation

Inverse trigonometric functions

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