trigonometry

Question: The general value $\theta $ is obtained from the equation $\cos 2\theta =\sin \alpha ,$ is

1) $2\theta =\frac{\pi }{2}-\alpha $

2) $\theta =2n\pi \pm \left( \frac{\pi }{2}-\alpha \right)$

3) $\theta =\frac{n\pi +{{(-1)}^{n}}\alpha }{2}$

4) $\theta =n\pi \pm \left( \frac{\pi }{4}-\frac{\alpha }{2} \right)$

Solution:

Explanation: No Explanation

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