trigonometry

Question: If in a triangle ABC, a, b, c and angle A is given and $c\sin A<a<c,$ then



1) ${{b}_{1}}+{{b}_{2}}=2c\cos A$
2) ${{b}_{1}}+{{b}_{2}}=c\cos A$
3) ${{b}_{1}}+{{b}_{2}}=3c\cos A$
4) ${{b}_{1}}+{{b}_{2}}=4c\sin A$
Solution: Explanation: No Explanation
Relation between sides and angles Solutions of triangles

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