trigonometry

Question: .Given that $\cos \left( \frac{\alpha -\beta }{2} \right)=2\cos \left( \frac{\alpha +B}{2} \right)$, then $\tan \frac{\alpha }{2}\tan \frac{\beta }{2}$is equal to

1) $\frac{1}{2}$

2) $\frac{1}{3}$

3) $\frac{1}{4}$

4) $\frac{1}{8}$

Solution:

Explanation: No Solution

Trigonometric ratios of multiple and sub-multiple angles

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