trigonometry

Question: $\sin 6\theta +\sin 4\theta +\sin 2\theta =0,$then $\theta =$



1) $\frac{n\pi }{4}$or $n\pi \pm \frac{\pi }{3}$
2) $\frac{n\pi }{4}$or $n\pi \pm \frac{\pi }{6}$
3) $\frac{n\pi }{4}$or $2n\pi \pm \frac{\pi }{6}$
4) None of these
Solution: Explanation: No Explanation
Solution of trigonometric equations

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