Categories > chemical-aritmatic > Chemical-Stoichiometry > $KMn{O_4}$ reacts with ferrous ammonium sulphate according to the equation $MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$, here 10 ml of 0.1 M $KMn{O_4}$ is equivalent to

chemical-aritmatic

Question: $KMn{O_4}$ reacts with ferrous ammonium sulphate according to the equation $MnO_4^ - + 5F{e^{2 + }} + 8{H^ + } \to M{n^{2 + }} + 5F{e^{3 + }} + 4{H_2}O$, here 10 ml of 0.1 M $KMn{O_4}$ is equivalent to


1) 20 ml of 0.1 M $FeS{O_4}$
2) 30 ml of 0.1 M $FeS{O_4}$
3) 40 ml of 0.1 M $FeS{O_4}$
4) 50 ml of 0.1 M $FeS{O_4}$
Solution: Explanation: No Explanation
Chemical-Stoichiometry

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