chemical-aritmatic

Question: A compound (80 g) on analysis gave $C = 24 g$, $H = 4 g$, $O = 32 g$. Its empirical formula is



1) ${C_2}{H_2}{O_2}$
2) ${C_2}{H_2}O$
3) $C{H_2}{O_2}$
4) $C{H_2}O$
Solution: Explanation: No Explanation
molecular-formula

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