chemical-aritmatic

Question: The number of sodium atoms in 2 moles of sodium ferrocyanide is

1) $12 \times {10^{23}}$

2) $26 \times {10^{23}}$

3) $34 \times {10^{23}}$

4) $48 \times {10^{23}}$

Solution:

Explanation: No Explanation

mole-concept

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