chemical-aritmatic

Question: The number of molecules in 16 g of methane is

1) $3.0 \times {10^{23}}$

2) $6.02 \times {10^{23}}$

3) $\frac{{16}}{{6.02}} \times {10^{23}}$

4) $\frac{{16}}{{3.0}} \times {10^{23}}$

Solution:

Explanation: No Explanation

mole-concept

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