chemical-aritmatic

Question: The total number of protons in 10 g of calcium carbonate is (${N_0} = 6.023 \times {10^{23}}$)

1) $1.5057 \times {10^{24}}$

2) $2.0478 \times {10^{24}}$

3) $3.0115 \times {10^{24}}$

4) $4.0956 \times {10^{24}}$

Solution:

Explanation: No Explanation

mole-concept

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