differentiation

Question: If $y = \frac{{{a^{{{\cos }^{ - 1}}x}}}}{{1 + {a^{{{\cos }^{ - 1}}x}}}}$and $z = {a^{{{\cos }^{ - 1}}x}}$, then $\frac{{dy}}{{dx}}$=

1) $\frac{1}{{1 + {a^{{{\cos }^{ - 1}}x}}}}$

2) $ - \frac{1}{{1 + {a^{{{\cos }^{ - 1}}x}}}}$

3) $\frac{1}{{{{(1 + {a^{{{\cos }^{ - 1}}x}})}^2}}}$

4) None of these

Solution:

Explanation: Explanation

standard-differentiation

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