differentiation

Question: If $y = {\cot ^{ - 1}}({x^2})$, then $\frac{{dy}}{{dx}}$ is equal to



1) $\frac{{2x}}{{1 + {x^4}}}$
2) $\frac{{2x}}{{\sqrt {1 + 4x} }}$
3) $\frac{{ - 2x}}{{1 + {x^4}}}$
4) $\frac{{ - 2x}}{{\sqrt {1 + {x^2}} }}$
Solution: Explanation: Explanation
standard-differentiation

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