differentiation

Question: If $u=\log ({{x}^{3}}+{{y}^{3}}+{{z}^{3}}-3xyz)$, then $\left( \frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z} \right)$ $(x+y+z)$ =



1) 0
2) 1
3) 2
4) 3
Solution: Explanation: No Explanation
Partial differentiation

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