differentiation

Question: If $f(x) = \sqrt {1 + {{\cos }^2}({x^2})} $, then $f'\left( {\frac{{\sqrt \pi }}{2}} \right)$ is

1) $\sqrt \pi /6$

2) $ - \,\sqrt {(\pi /6)} $

3) $1/\sqrt 6 $

4) $\pi /\sqrt 6 $

Solution:

Explanation: Explanation

standard-differentiation

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