If $y = \frac{{{e^{2x}}\cos x}}{{x\sin x}},$then $\frac{{dy}}{{dx}} = $

Question

Accepted Answer

$\frac{{{e^{2x}}[(2x - 1)\cot x - x\,{\rm{cose}}{{\rm{c}}^2}x]}}{{{x^2}}}$

Answer

$\frac{{{e^{2x}}[(2x + 1)\cot x - x\,{\rm{cose}}{{\rm{c}}^2}x]}}{{{x^2}}}$

Answer

$\frac{{{e^{2x}}[(2x - 1)\cot x + x\,{\rm{cose}}{{\rm{c}}^2}x]}}{{{x^2}}}$

Answer

None of these

differentiation